Subnet Calculator (CIDR)
Network, broadcast, mask and host count from CIDR
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Need a fast answer on network, broadcast, mask and host count from CIDR? Subnet Calculator (CIDR) answers with the steps beside it. Enter IPv4 Address and Prefix (/bits) in any order — Subnet Calculator (CIDR) recalculates on every edit. Subnet Calculator (CIDR) prints the result and its working. Subnet Calculator (CIDR) works for one check or many. Subnet Calculator (CIDR) is privacy-first: Tech & Digital inputs stay offline. Subnet Calculator (CIDR) handles subnet calculator cidr ipv4 netmask broadcast hosts network range the same way as free online subnet calculator (cidr) — one of the Tech & Digital tools on CalcProMaster. The labels in Subnet Calculator (CIDR) match the terms in its result. Open Subnet Calculator (CIDR) and enter your numbers.
What /26 does to this address
With a /26 prefix, 192.168.1.10 sits in the network 192.168.1.0, mask 255.255.255.192, broadcast 192.168.1.63, with 62 usable hosts.
A /26 fixes 26 bits as network and leaves 6 for hosts, so the block is 64 addresses — small enough that four of them split a /24 exactly.
From prefix to mask
The prefix counts leading 1 bits in the 32-bit mask. /26 sets 26 bits, leaving 6 host bits: 255.255.255.192, because the last octet is 11000000 in binary — 192.
Block size follows from the remaining bits: 2⁶ = 64 addresses. Usable hosts are 64 − 2 = 62.
Worked example: 192.168.1.10/26
Mask: 255.255.255.192
Block size: 64
Network: 192.168.1.0
First host: 192.168.1.1
Last host: 192.168.1.62
Broadcast: 192.168.1.63
The next subnet begins at 192.168.1.64, then .128 and .192 — four /26s fill the /24 exactly.
The mask last octet for each prefix
- /24 → 0
- /25 → 128 (2 subnets, 126 hosts)
- /26 → 192 (4 subnets, 62 hosts)
- /27 → 224 (8 subnets, 30 hosts)
- /28 → 240 (16 subnets, 14 hosts)
- /30 → 252 (64 subnets, 2 hosts)
Why 192.168.1.10 lands in .0 rather than .64
Subnets run in blocks of 64 from zero: 0–63, 64–127, 128–191, 192–255. The address 10 falls inside the first block, so its network is .0. A /26 at .70 would sit in the second block, with network .64 and broadcast .127.
What this does not tell you
Whether the subnet is already in use, what the gateway is, or how it is routed. The calculation is arithmetic on an address; the network design decisions sit above it.
Frequently Asked Questions
Why does /26 give 62 hosts?
Because 6 host bits remain, giving 2^6 = 64 addresses. Two of them — network and broadcast — cannot be assigned, leaving 62 usable.
What is the mask for /26?
255.255.255.192. The last octet 192 is 11000000 in binary, so two bits are added to the network portion compared with /24.
Which subnet does 192.168.1.10/26 belong to?
192.168.1.0 — the block runs from .0 to .63. The next subnet starts at .64, so addresses .64–.127 form the second one.
How many /26 subnets fit in a /24?
Four: .0/26, .64/26, .128/26 and .192/26. Four blocks of 64 addresses make the 256 of the /24.
Is /31 usable for hosts?
Yes, on point-to-point links (RFC 3021) where both addresses are usable. For ordinary LAN segments, /30 is the smallest practical subnet with two usable hosts.
How do I split a /24 into four /26 subnets?
Use block starts of 0, 64, 128 and 192 in the last octet: 192.168.1.0/26, .64/26, .128/26 and .192/26. Each is 64 addresses wide with 62 usable, so together they fill the 256 addresses of the original /24 exactly.
Which subnet does 192.168.1.200 belong to?
The fourth block, 192.168.1.192/26, which runs from .192 to .255. Its usable hosts are .193 to .254 and its broadcast is .255. Reading the block boundaries from 0 in steps of 64 answers this for any address.
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